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Consider the situation shown in figure. The frame is made of the same material and has a uniform cross-sectional area everwhere. If amount of heat flowing per second through a cross-section of part `A` is `60J`. The amount of total heat taken out per second from the end at `50^(@)C` is `0.132 xx 10^(n) J//s`. Find 'n'.

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The correct Answer is:
3


`R_(1) =` thermal resistance of bent part
`= (60)/(KA), R_(2) = (50)/(KA)`
`((R_(2))/(R_(1)+R_(2))) Q = 60 J//s rArr Q = 132 J//s`
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