Two spherical bodies A (radius 6cm) and B (radius 18cm) are at temperature `T_(1)` and `T_(2)` respectively The maximum intensity in the emission spectrum of A is at `500 nm` and in that of `B` is at `1500nm` considering them to be black bodies, what will be the ratio of the rate of total energy radiated by A to that of `B` . ?

Answer

9

Explanation

`(lambda_(m))_(B) = 3(lambda_(m))_(A)`
`rArr T_(A) = 3T_(B)`
`E_(1) = 4pi (6)^(2) sigma T_(A)^(4) = 4pi(6)^(2) (3T_(B))^(4)`
`E_(2) = 4pi (18)^(2) sigma T_(B)^(4)`
`(E_(1))/(E_(2)) = 9`.