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Given that the roots of the equation 24...

Given that the roots of the equation ` 24x^(3) - 26x^(2) + 9x - 1 = 0` are in HP , find them

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Equation ` 24 x^(3) - 26x^(2) + 9x - 1 = 0 ` has its roots in H.P.
Let ` x = (1)/(y)`
` rArr (24)/(y^(3)) - (26)/(y^(2)) + (9) /(y) -1 = 0 `
` y^(3) - 9y^(2) + 26y - 24 = 0 ` has its roots in A.P.
Let the roots be
` alpha = a - d , beta = a , gamma = a+ d `
` alpha + beta + gamma = 3a = 9`
` rArr a = 3 `
` alpha beta gamma = a (a^(2) - d^(2)) = 24`
` rArr a^(2) - d^(2) = 8`
` rArr d^(2) = 1`
`rArr d = pm 1`
` alpha = 2 , beta = 3 , gamma = 4 `
`rArr ` Roots of original equation are `(1)/(2), (1)/(3), (1),(4)`
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