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the value of 5^(log7 11)-1 1^(log7 5) is...

the value of `5^(log_7 11)-1 1^(log_7 5)` is

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Let ` 5^(log7^(11)) = a and 11^(log7^(5)) = b `
so that ` log_(5)a = log_(7)11 and log_(11) b = log_(7) 5 `
`rArr log_(5) a xx log_(7)5 = log_(7) 11 xx log_(11)b `
` rArr log_(7)a = log_(7) b `
`rArr a = b `
`rArr a - b= 0 `
` rArr 5^(log_(7)11) - 11^(log_(7)5) = 0 `
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