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Show that for the sequence defined by ` a_(n) = (n -1) (n-2) ` ,the first two terms are zero and ltbRgt its fifth term is 12 .

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Given , `a_(n) = (n-1) (n-2)`
` therefore a_(1) = 0 xx (1-2) = 0`
` a_(2) =0 xx (1-2) = 0 `
` a_(2) = (2- 1) xx 0 = 0 `
` and a_(5) = (5 -1) (5-2) = 4 xx 3 = 12 ` .
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