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(sin A+ sin 3A +sin 5 A+ sin 7A)/ ( cos ...

` (sin A+ sin 3A +sin 5 A+ sin 7A)/ ( cos A + cos 3A +cos 5A+ cos 7A)=tan 4A`

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We have,
`LHS = ((sin7A + sinA) + (sin5A+ sin3A))/((cos7A+ cos3A + cos5A + cos7A))`
`=(sin4A cos3A + sin4AcosA)/(cos4A cos3A + cos4A cosA)`
`=(sin4A(cos3A + cosA))/(cos4A (cos3A +cosA))=tan4A = RHS`
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AAKASH INSTITUTE-TRIGNOMETRIC FUNCTIONS -Section - J (Akash Challengers Question)
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