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If 5tan alpha tan beta=3, then find the ...

If `5tan alpha tan beta=3`, then find the value of `(cos(alpha+beta))/(cos(alpha-beta))`

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`5tanalphatanbeta=3`
`rArr (5sinalphasinbeta)/(cos alpha cos beta)=3`
`rArr (cos alpha cos beta)/(sin alpha sin beta)=5/3`
Using compenendon and dividendo.
`(cos alpha cos beta+ sin alpha sin beta)/(cos alpha cos beta- sin alpha sin beta)=(5+3)/(5-3)=8/2=4`
`rArr (cos(alpha-beta))/(cos(alpha-beta))=1/4`
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