In `triangle ABC`, if a=3, b=4, and c=5, then find the value of cosA.

Explanation

To find the value of \( \cos A \) in triangle \( ABC \) where \( a = 3 \), \( b = 4 \), and \( c = 5 \), we can use the cosine rule. The cosine rule states that:

\[ \cos A = \frac{b^2 + c^2 - a^2}{2bc} \]

### Step-by-step Solution:

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