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If a ** b = 4a^(2) + 6b^(2) be a binary ...

If `a ** b = 4a^(2) + 6b^(2)` be a binary operations on Q, then verify that `**` is not commutative.

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`a ** b = 4a^(2) + 6b^(2)`
`b ** a = 4b^(2) + 6a^(2)`
`a ** b = b ** a` (for commutative)
`4a^(2) + 6b^(2) = 4b^(2) + 6a^(2)`
`2b^(2) = 2a^(2)`
`b = +- a`
So it is not commutative
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