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A bag contains 7 white, 5 black and 4 re...

A bag contains 7 white, 5 black and 4 red balls. If two balls are drawn at random, find the probability that: (i) both the balls are white (ii) one ball is black and the other red (iii) both the balls are of the same colour.

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There are 16 balls in the bag of which 2 balls can be drawn in `""^(16)C_(2)` ways.
So, total number of elementary events = `""^(16)C_(2)`
(i) There are 7 white balls out of which balls can be drawn in `""^(7)C_(2)` ways.
`therefore " Number of favourable outcomes = ""^(7)C_(2)`
So, required probability = `(""^(7)C_(2))/(""^(16)C_(2))=(7)/(40)`
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