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If two events A and B such that P(A')=0....

If two events `A` and `B` such that `P(A')=0.3`, `P(B)=0.5` and `P(AnnB)=0.3`, then `P(B//AuuB')` is

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`P(AcupB')=P(A)+P(B')-P(AcapB')`
`=[(1-P(A')]+[1-P(B)]-[P(A)-P(AcapB)]`
=0.8
`P(B|(AcupB'))=(P[Bcap(AcupB')])/(P[AcupB'])=(P[(BcapA)cup(BcapB')])/(P(AcupB'))`
`=(P(AcapB))/(P(AcupB'))=0.3/0.8=3/8`
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