One hundred identical coins each with probability p showing up heads are tossed once. `"If" 0 lt p lt 1` and the probability of heads showing on 50 coins is rqual to that of heads showing on 51 coins, then the value of p is

Explanation

P(X=51)=P(X=50)
`""^100C_51p^51q^49=""^100C_50p^50q^50, " " (q=1-p)`
`therefore " "p/q=(100!)/(50!50!)(5!49!)/(100!)`
`p/(1-p)=51/50 impliesp=51/101`