Home
Class 12
MATHS
A number is selected from first 100 natu...

A number is selected from first 100 natural numbers. The probability that number is perfect square or a perfect cube is

A

`7/50`

B

`3/25`

C

`2/25`

D

`1/25`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the probability that a number selected from the first 100 natural numbers is either a perfect square or a perfect cube, we can follow these steps: ### Step 1: Identify Perfect Squares First, we need to find all the perfect squares from the first 100 natural numbers. A perfect square is a number that can be expressed as the square of an integer. The perfect squares from 1 to 100 are: - \(1^2 = 1\) - \(2^2 = 4\) - \(3^2 = 9\) - \(4^2 = 16\) - \(5^2 = 25\) - \(6^2 = 36\) - \(7^2 = 49\) - \(8^2 = 64\) - \(9^2 = 81\) Thus, the perfect squares are: **1, 4, 9, 16, 25, 36, 49, 64, 81**. **Count of perfect squares = 9.** ### Step 2: Identify Perfect Cubes Next, we find all the perfect cubes from the first 100 natural numbers. A perfect cube is a number that can be expressed as the cube of an integer. The perfect cubes from 1 to 100 are: - \(1^3 = 1\) - \(2^3 = 8\) - \(3^3 = 27\) - \(4^3 = 64\) Thus, the perfect cubes are: **1, 8, 27, 64**. **Count of perfect cubes = 4.** ### Step 3: Identify Overlap (Common Elements) Now we need to check if there are any numbers that are both perfect squares and perfect cubes. These numbers are perfect sixth powers (since \(n^6 = (n^2)^3 = (n^3)^2\)). The perfect sixth powers from 1 to 100 are: - \(1^6 = 1\) - \(2^6 = 64\) Thus, the common numbers are: **1, 64**. **Count of common elements = 2.** ### Step 4: Calculate Total Favorable Outcomes Using the principle of inclusion-exclusion, we can calculate the total count of favorable outcomes: - Count of perfect squares = 9 - Count of perfect cubes = 4 - Count of common elements = 2 Total favorable outcomes = (Count of perfect squares) + (Count of perfect cubes) - (Count of common elements) \[ = 9 + 4 - 2 = 11 \] ### Step 5: Calculate Total Outcomes The total number of outcomes when selecting from the first 100 natural numbers is: \[ \text{Total outcomes} = 100 \] ### Step 6: Calculate Probability Now, we can calculate the probability using the formula: \[ \text{Probability} = \frac{\text{Favorable outcomes}}{\text{Total outcomes}} = \frac{11}{100} \] ### Final Answer The probability that a number selected from the first 100 natural numbers is either a perfect square or a perfect cube is: \[ \frac{11}{100} \text{ or } 0.11 \] ---
Promotional Banner

Topper's Solved these Questions

  • PROBABILITY

    AAKASH INSTITUTE|Exercise ASSIGNMENT (SECTION - C Objective Type Questions (More than one options are correct))|21 Videos
  • PROBABILITY

    AAKASH INSTITUTE|Exercise ASSIGNMENT (SECTION - D Linked Comprehension Type Questions)|21 Videos
  • PROBABILITY

    AAKASH INSTITUTE|Exercise ASSIGNMENT (SECTION - A Competition Level Questions)|114 Videos
  • PRINCIPLE OF MATHEMATICAL

    AAKASH INSTITUTE|Exercise Section-D:(Assertion-Reason Type Questions)|12 Videos
  • RELATIONS AND FUNCTIONS

    AAKASH INSTITUTE|Exercise Assignment (Section - J) Aakash Challengers Questions|8 Videos

Similar Questions

Explore conceptually related problems

A number is chosen at random from first ten natural numbers. The probability that number is odd and perfect square is .

Three distinct number are selected from first 100 natural numbers. The probability that all the numbers are divisible by 2 and 3 is _________

Three distinct numbers are selected from the first 100 natural numbers. The probability that all the three numbers are dicisible by 2 and 3 is

Two numbers are randomly selected from the first 100 natural numbers. The probability the product is divisible by 17 is

Two distinct numbers are selected from the numbers 1,2,3,...9. Then probability that their product is a perfect square is

The number of two digit numbers which are perfect square and perfect cube both is :

The number which is not a perfect square is-

A natural number 'n' is selected at random from the set of first 100 numbers. The probability that n+(100)/(n)le 50 equal to

AAKASH INSTITUTE-PROBABILITY-ASSIGNMENT (SECTION - B Objective Type Questions (One option is correct))
  1. If P(A) = 1/2 and P(AcapB)=1/3, then the probability that A happens bu...

    Text Solution

    |

  2. Three distinct numbers are selected from the first 100 natural numbers...

    Text Solution

    |

  3. A number is selected from first 100 natural numbers. The probability t...

    Text Solution

    |

  4. Five horses are in race. Mr. X selected two of horses at random and b...

    Text Solution

    |

  5. 5 cards are drawn from a pack of 52 cards. The probability that these ...

    Text Solution

    |

  6. Let n = 2^3 4^5 6^8 5^4. A positive factor is taken atrandom from the ...

    Text Solution

    |

  7. If p and q are chosen randomly from the set {1, 2, 3, ………, 10} with re...

    Text Solution

    |

  8. 12 members of a committee are to sit down at random round a table. Pro...

    Text Solution

    |

  9. Two integers x and y are chosen with replacement out of the set {0, 1,...

    Text Solution

    |

  10. Dialing a telephone number, an old man forgets the last two digits rem...

    Text Solution

    |

  11. There are four balls of different colours and four boxes of colours sa...

    Text Solution

    |

  12. Four digit number is formed from all possible ways. The probability th...

    Text Solution

    |

  13. If P(B) = 3/4, P(AcapBcapbarC)=1/3 and P(barAcapBcapbarC)=1/3, then ...

    Text Solution

    |

  14. Given two events A and B. If odds against A are 2 : 1 and those in fov...

    Text Solution

    |

  15. A bag contains 5 brown and 4 white socks. A man pulls out two socks. ...

    Text Solution

    |

  16. Two numbers are selected randomly from the set S={1,2,3,4,5,6} without...

    Text Solution

    |

  17. Out of 20 consecutive numbers, two are chosen at random, the probabili...

    Text Solution

    |

  18. Out of n persons sitting at a round table, three, A, B, C are chosen a...

    Text Solution

    |

  19. In a singing competition a group of 10 pepole, participate, each perso...

    Text Solution

    |

  20. If A and B are two independent events such that P(A) = 7/10, P(B')=alp...

    Text Solution

    |