A bullet of mass 50 g is fired from a gun with initial velocity of 35 m/s . If mass of the gun is 4 kg , then calculate the recoil velocity of the gun .

Explanation

We have
Mass of the bullet ` m_(1) = 50 g = 50 xx 1-10^(-3)"Kg"`
Speed of the bullet `v_(1) = 35 m//s`
Mass of thegun `m_(2) = 4 "kg"`
Velocity of the gun `v_(2) = ?`
According to the conversation of momentum ,
Total momentum before firing = Total momentum after firing
But total momentum before firing = 0
Because the bullet gun system will be zero after collision
` m_(1) v_(1) + m_(2)v_(2) = 0`
` :. v_(2) = (-m_(1)v_(1))/(m_(2)) `
` :. v_(2) = (-0*05 xx 35)/4 = - 0*4375 m//s cong =0* 44 m//s`
The negative sign shows that the gun moves opposite to the direction of motion of the bullet .