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A variable force acts on a body of mass ...

A variable force acts on a body of mass 2 kg initially at rest as shown in figure . Calculate the impulse of the force in first 2 seconds and speed of the body after 2 seconds .

Text Solution

Verified by Experts

Impulse of a force area under force time curve thus,
Area of ` Delta OAB = 1/2 xx 2 xx 10 = 10 N s`
Thus impulse equals 10 s
Now, impulse equal change in momentum
` rArr 10 = mv - 0 `
` V = 10/2 rArr 5 m//s`
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