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A short electric dipole is placed along ...

A short electric dipole is placed along y-axis at the origin. The electric field vector at a point P on x-axis is `vec(E ) _(1)`. The dipole is rotated by `( pi)/(2)` at its position . Now, the electric field vector at point P is `vec(E )_(2)`. Select the correct alternative(s) `:`

A

`vec(E )_(2)= - vec(E )_(1)`

B

`vec(E )_(2)= - 2vec(E )_(1)`

C

`|vec(E )_(2)| = - 2|vec(E )_(1)|`

D

`vec(E )_(2) . vec( E )_(1)=0`

Text Solution

Verified by Experts

The correct Answer is:
(3,4)
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Knowledge Check

  • An electric dipole is placed along x -axis with its centre at origin:

    A
    The electric field is perpendicular to each and every point on `y-z` plane
    B
    `y-z` plane is an equipotential surface
    C
    `y-z` plane is not equipotential surface
    D
    Flux of electrix field enclosing dipole is zero
  • Point P lies on the axis of a dipole . If the dipole is rotated by 90^@ anticlock wise , the electric field vectro vec E at P will rotate by .

    A
    ` 90^@ ` Clock wise
    B
    ` 180^@` clock wise
    C
    ` 90 ^@` anti clock wise
    D
    none
  • A short electric dipole is oriented along x-direction at origin. At which of following point the electric field have no x component.

    A
    `(1,1,0)`
    B
    `(sqrt(2),1,0)`
    C
    `(1,sqrt(2),0)`
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