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In the network shown in given figure, f...

In the network shown in given figure, find the potential difference across BD

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Resistance of branck `ABC = ( 10 + 5) Omega = 15 Omega `
Resistance of branch `ADC = ( 10 + 5) Omega = 15 Omega `
Both branches are parallel across the cell 3V
Current through both branches are

`l_(1) = ( 3V)/( 15Omega ) = ( 1)/(5) A` and `l_(2) = ( 3V)/( 15 Omega) = (1)/(5) A`
Potential difference across BD
`V_(B) -V_(D) = ( V_(B) - V_(A))= (V_(A) - V_(D))`
`= - 5 l_(1) + 10 l_(2) `
`= - 5 xx (1)/(5) + 10 xx (1)/(5) `
`= 1 V `
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