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For m ne n, if "tan" m theta = "tan" n t...

For `m ne n`, if `"tan" m theta = "tan" n theta`, then different values of `theta` are in

A

A.P

B

H.P

C

G.P

D

no particular sequence

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The correct Answer is:
To solve the equation \( \tan(m\theta) = \tan(n\theta) \) for \( m \neq n \), we can follow these steps: ### Step 1: Understand the condition The equation \( \tan(m\theta) = \tan(n\theta) \) implies that the angles \( m\theta \) and \( n\theta \) differ by an integer multiple of \( \pi \). This can be expressed as: \[ m\theta = n\theta + k\pi \quad \text{for some integer } k \] ### Step 2: Rearranging the equation Rearranging the equation gives us: \[ m\theta - n\theta = k\pi \] This simplifies to: \[ (m - n)\theta = k\pi \] ### Step 3: Solve for \( \theta \) Now, we can isolate \( \theta \): \[ \theta = \frac{k\pi}{m - n} \] ### Step 4: General solution Since \( k \) can be any integer, we can express the general solution for \( \theta \) as: \[ \theta = \frac{k\pi}{m - n} \quad \text{where } k \in \mathbb{Z} \] ### Step 5: Identify the sequence of solutions The values of \( \theta \) will form an arithmetic progression (AP) with a common difference of: \[ \frac{\pi}{m - n} \] Thus, the different values of \( \theta \) are: \[ \theta = \frac{\pi}{m - n}, \frac{2\pi}{m - n}, \frac{3\pi}{m - n}, \ldots \] ### Conclusion The different values of \( \theta \) are in an arithmetic progression with a common difference of \( \frac{\pi}{m - n} \). ---
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  13. The most general solution of the equation 8"tan"^(2) (theta)/(2) = 1...

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  17. The equation sin x + sin y + sin z =-3 for 0 le x le 2pi , 0 le y l...

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