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The difference rate law for the reaction...

The difference rate law for the reaction
`H_(2) +I_(2) to 2HI` is

A

`-(d[H_(2)])/(dt)=-(d[I_(2)])/(dt)=-(d[HI])/(dt)`

B

`(d[H_(2)])/(dt)=(d[I_(2)])/(dt)=(1)/(2)(d[HI])/(dt)`

C

`(1)/(2)(d[H_(2)])/(dt)=(1)/(2)(d[I_(2)])/(dt)=-(d[HI])/(dt)`

D

`-2(d[H_(2)])/(dt)=-2(d[I_(2)])/(dt)=(d[HI])/(dt)`

Text Solution

Verified by Experts

The correct Answer is:
D
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