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A(g)rarrB(g)+C(g) -(d[A])/(dt)=k[A] ...

`A(g)rarrB(g)+C(g)`
`-(d[A])/(dt)=k[A]`
At the start, pressure is 100 mm and after 10 min, pressure is 120 mm. Hence, rate constant `("min"^(-1))` is :

A

`(2.303)/(10)"log"(120)/(100)`

B

`(2.303)/(10)"log"(100)/(20)`

C

`(2.303)/(10)"log"(100)/(80)`

D

`(2.303)/(10)"log"(100)/(120)`

Text Solution

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The correct Answer is:
C
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GRB PUBLICATION-CHEMICAL KINETICS-C. Integrated Rate Laws
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