The mechanism of reaction :`A(g) overset(pt(s))rarrB(g)` is :
Step-I: A(g) + Surface sites `underset(k_(2))overset(k_(1))hArr A ` (absorbed)
Step-II: A (absorbed) `overset(k_(3))rarr B(g)+` Surface sites
The rate law of this reaction s `r=(k_(1)k_(3)[A])/(k_(2)+k_(1)[A])` (for fixed number of surface sites.)
The only incorrect information regarding the reaction is :

Options

A. Step-I may be a fast equilibrium and Step-Ii, RDS.
B. At very low concentration of 'A' , the reaction is first order w.r.t. 'A'.
C. At very high concentration of 'A' , the rate becomes independent from of 'A' but depends on the surface sites.
D. At very high concentration of 'A' , the rate depends on the concentration of 'A' as well as on suface sites.

Answer

D