Molecule of a gas in a container hits one wall (1) normally and rebounds back. It suffers number of collision and hits the opposite wall (2) which is at angle of `30^(@)` with wall 1. Assuming the collision to be elastic and the small collision time to be the same for both the walls. The magnitude of average force by walls and 2 are `F_(1)` and `F_(2)` provide to molecule during collision satisfy

Options

A. `F_(1) gt F_(2)`
B. `F_(1) lt F_(2)`
C. `F_(1)=F_(2)` both non zero
D. `F_(12)F_(220)`

Answer

A

Explanation

`F_(1) = (2mv)/(Deltat)" " F_(2)= (2mvcos30^(@))/(Deltat)`
Hence `F_(1) gt F_(2)`