A cubical box of side `1 m` contains an ideal gas ata pressure `100 N//m^(2)`. If `Sigmav_(x)^(2) = Sigmav_(y)^(2) = Sigmav_(z)^(2) = 10^(28) m^(2)//s^(2)`, where `v_(x), v_(y)` and `v_(z)` are the x, y and z components, respectively, of the gas molecule, then the mass of each gas molecule is

Options

A. `10^(-20) g`
B. `10^(-23) g`
C. `10^(-18) g`
D. `10^(-26) g`

Answer

B

Explanation

`PV=mSigmav_(x)^(2)`
`rArr m = (100xx1)/(10^(28))=10^(-26) Kg = 10^(-23)g`