A uniformly charged square plate having side L carries a uniform surface charge density `sigma`. The plate lies in the `y - z` plane with its centre at the origin. A point charge q lies on the x-axis. The flux of the electric field of q through the plate is `phi0`, while the foce on the point charge q due to the plate is `F_(0)`, along the x-axis. Then,

Options

A. `sigma = (F_(0))/(phi_(0)L)`
B. `sigma = (F_(0))/(phi_(0))`
C. `sigma = (F_(0)L)/(phi_(0))`
D. `sigma = (phi_(0))/(F_(0))`

Answer

B

Explanation

The correct answer can be determined by dimensional analysis.