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A parent radioactive nucleus A (decay co...

A parent radioactive nucleus A (decay constant `lamda_(A))` converts into a radio-active nucleus B of decay constant `lamda_(b)`, initially, number of atoms of B is zero At any time `N_(a),N_(b)` are number of atoms of nuclei A and B respectively then maximum velue of `N_(b)`.

A

`(D_(A) N_(A))/(D_(B))`

B

`(D_(B) N_(A))/(D_(A))`

C

`((D_(A) + D_(B)) N_(A))/(D_(B))`

D

`(D_(B))/((D_(A) + D_(B)) N_(A)`

Text Solution

Verified by Experts

The correct Answer is:
A
`N_(B)` reaches maximum when activeity of A and B will be same
i.e `D_(A) N_(A) = D_(B)N_(B) :. N_(B) = (D_(A)N_(A))/(D_(B))`
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