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Acceleration of a paritcle moving in x-y...

Acceleration of a paritcle moving in `x-y` plane varies with time t as. `vec(a) = (ti + 3T^(2)j)`.
Here a is in `m//s^(2)` and t in sec. At time `t = 0` particle is at rest origin. Mass of the particles is `1 kg`. Find the net work done on the particle in first `2 sec`.

A

`40 J`

B

`34 J`

C

`16 J`

D

`48 J`

Text Solution

Verified by Experts

The correct Answer is:
B
`(d vec(v))/(dt) = ti + 3t^(2)j :. int_(o)^(v )d vec(v ) = int_(o)^(2)(ti + 3t^(2)j)dt`
`:. vec(v ) = (2i + 8j)m//s`
`:. v = sqrt68`
by work energy theorem `:. w = (1)/(2)mv^(2) :. w = 34J`
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