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The displacement of a body from a refere...

The displacement of a body from a reference point is given by `sqrt(x)=2t-3`, where `'x'` is in metres and it is non negative number, `t` in seconds. This shows that the body `:`

A

is at rest at `t=3//2`

B

is speeding up for `tgt3//2`

C

is retarded for `tlt3//2`

D

is in uniform motion

Text Solution

Verified by Experts

The correct Answer is:
A, B, C
`sqrt(x)=(2t-3)` for `B` option
`x=(2t-)^(2)` acceleration
for `tgt3//2`
`(dx)/(dt)=2(2t-2)(2)=4(2t-3)`,
`V=4(2t-3)=0`
rest at `t=3//2`
`a=8m//s`.
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