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A point moves in a straight line so its ...

A point moves in a straight line so its displacement `x` meter at time `t` second is given by `x^(2)=1+t^(2)`. Its acceleration in `ms^(-2)` at time `t` second is .

A

`(1)/(x^(3))`

B

`(1)/(x)-(1)/(x^(2))`

C

`-(t)/(x^(2))`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
`x^(2)=t^(2)+1`
`2x(dx)/(dt)=2t`
`rArr xV=t`
`xa+V^(2)=1`
`a=(1-V^(2))/(x)=(1-(t^(2))/(x^(2)))/(x)`
`rArra=(x^(2)-t^(2))/(x^(3))=(1)/(x^(3))`
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