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A clock has it's minute-hand 10 cm long....

A clock has it's minute-hand `10 cm` long. Find the average velocity between `6.00 AM` to `6.30AM` for the tip of minute-hand.

A

`(22)/(21)cmm i n^(-1)`

B

`(2)/(21)cm mi n^(-1)`

C

`(12)/(21)cm mi n^(-1)`

D

`(2)/(3)cmmi n^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
From `6:00 AM` to `6:30 AM` displacement of tip of minute hand
`=2xx10cm =20cm`
Hence, average velocity `=(20cm)/(30 mi n)=(2)/(3)cm mi n^(-1)`
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