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A particle A is projected with speed V(A...

A particle `A` is projected with speed `V_(A)` from a point making an angle `60^(@)` with the horizontal. At the same instant, second particle `B(` lie in the same horizontal plane `)` is thrown vertically upwards from a point directly below the maximum height point of parabolic path of `A`, with velocity `V_(B)`. If the two particles collide then the ratio of `V_(A)//V_(B)` should be `:`

A

1

B

`2//sqrt(3)`

C

`sqrt(3)//2`

D

`sqrt(3)`

Text Solution

Verified by Experts

The correct Answer is:
B
`V_(A)sin 60^(@)=V_(B)`
`rArr (V_(A))/(V_(B))=(2)/(sqrt(3))`
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