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A stone projected at angle 'theta' with...

A stone projected at angle `'theta'` with horizontal from the roof of a tall building talls on the ground after three second. Two second after the projection it was again at the level of projection. Then the height of the building is `-`

A

`5m`

B

`25m`

C

`2m`

D

`15m`

Text Solution

Verified by Experts

The correct Answer is:
D
`2=(2u_(y))/(g)rArru_(y)=10m//s`

Now, `H=-u_(y)t+(1)/(2)g t^(2)`
`=-30+45=15m`.
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Knowledge Check

  • A stone projected at angle theta with horizontal from the roof of a tall building falls on the ground after three seconds. Two second after the projection it was again at the level of projection. Then the height of the building

    A
    `5m`
    B
    25 m
    C
    20m
    D
    15m

  • If a body is projected with an angle theta to the horizontal, then

    A
    its velocity is always perpendicular to its acceleration
    B
    its velocity becomes zero at its maximum height.
    C
    its velocity makse zero angle with the horizontal at its maximum height
    D
    the body just before hitting the ground, the direction of velocity coincides with the acceleration

  • A particle is projected at an angle theta with the horizontal . If angle of elevation of highest point of trajectory is phi when seen from point of projection, then

    A
    `tan phi =2 tan phi`
    B
    `tan theta =3 tan phi`
    C
    `tan theta =2 tan phi`
    D
    `tan theta=4 tan phi`

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