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A stone projected at angle 'theta' with...

A stone projected at angle `'theta'` with horizontal from the roof of a tall building talls on the ground after three second. Two second after the projection it was again at the level of projection. Then the height of the building is `-`

A

`5m`

B

`25m`

C

`2m`

D

`15m`

Text Solution

Verified by Experts

The correct Answer is:
D
`2=(2u_(y))/(g)rArru_(y)=10m//s`

Now, `H=-u_(y)t+(1)/(2)g t^(2)`
`=-30+45=15m`.
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