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A particle is projected under gravity at...

A particle is projected under gravity at an angle of projection `45^(@)` with horizontal. Its horizontal range is `36m`. Find maximum Height attained by particle.

Text Solution

Verified by Experts

The correct Answer is:
9
`(H)/(R)=(tantheta)/(4)`
`theta 45^(@) & R=36m`
`H=9m`
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