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A bota has a velocity 4m//s towards east...

A bota has a velocity `4m//s` towards east with respect to river is flowing north with velocity `2m//s` Wind is blowing towards north with velocity `6m//s`. The direction of the flag blown over by the wind hoisted on the boat is `:`

A

north`-`west

B

south`-`east

C

`tan^(-1)``(1)/(2)` with east

D

north

Text Solution

Verified by Experts

The correct Answer is:
A
Vboat , river `=4hat(i)`
Vriver,ground`=2hat(i)`
Vwind, ground`=6hat(j)`

`vec(V)` wind , boat `=vec(V)_(wg)+vec(V)_(gr)+vec(V)_(rb)=6hat(j)-2hat(j)-4hat(i)=-4hat(i)+4hat(j)`
so flag blown in north west.
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