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Two blocks of masses m(1)=2kg and m(2)=5...

Two blocks of masses `m_(1)=2kg` and `m_(2)=5kg` hang over a massless pulley as shown in the figure. A force `F_(0)=100N` acting at the axis of the pulley accelerates the system upwards. Then `: (` Take `g=9.8m//s^(2))`

A

Acceleration of 2kg mass is `15.2m//sec^(2)`

B

Acceleration of `5kg` mass is `0.2m//sec^(2)`

C

Acceleration of both the masses is same

D

Acceleration of both the masses is upward

Text Solution

Verified by Experts

The correct Answer is:
A, B, D

`50-2g=2a`
`(50-19.6)/(2)=a`
`a=15.2 m//sec^(2)` upwards
As the acceleration of both the masses is upward.

and also, `50-5g=5b`
`(50-5xx9.8)/(2)=b`
`b=(50-49)/(5)=0.2m//sec^(2)` also upwards`
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