Home
Class 11
PHYSICS
A block of mass 5 kg is released from re...

A block of mass `5 kg` is released from rest when compression in spring is `2m`. Block is not attached with spring and natural length of the spring in `4m`. Maximum height of block from ground is `:(g=10m//s^(2))`

A

`5.5m`

B

`4.5m`

C

`6m`

D

`7.5m`

Text Solution

Verified by Experts

The correct Answer is:
A
By energy conservation,

`(1)/(2)kx^(2)=mgh+(1)/(2)mv^(2)`
`=(1)/(2)xx300xx(2)^(2)=5xx10xx2+(1)/(2)xx5v^(2)`
`=v^(2)=200`
Also, `H=(v^(2)sin^(2)30^(@))/(2g)=2.5m`
So, total height from ground `=3+2.5=5.5m`
Promotional Banner

Topper's Solved these Questions

  • DAILY PRACTICE PROBLEMS

    RESONANCE|Exercise dpp 39|3 Videos

  • DAILY PRACTICE PROBLEMS

    RESONANCE|Exercise dpp 40|5 Videos

  • DAILY PRACTICE PROBLEMS

    RESONANCE|Exercise Dpp 37|8 Videos

  • CURRENT ELECTRICITY

    RESONANCE|Exercise Exercise|54 Videos

  • ELASTICITY AND VISCOCITY

    RESONANCE|Exercise Advanced Level Problems|9 Videos

Similar Questions

Explore conceptually related problems

A block is released from height h , find the maximum compression of spring of spring constant k .

The block of mass m is released when the spring was in its natrual length. Spring constant is k. Find the maximum elongation of the spring.

A block of 200 g mass is dropped from a height of 2 m on to a spring and compress the spring to a distance of 50 cm. The force constant of the spring is

A block of mass m is released from rest at point A. The compression in spring (force constant k) when the speed of block is maximum is found to be (nmg cos theta)/(4k) . What should be the value of n?

The block shown in figure is released from rest. Find out the speed of the block when the spring is compressed by 1 m

In the figure shown, the system is released from rest with both the springs in unstretched positions. Mass of each block is 1 kg and force constant of each spring is 10 N/m. Maximum speed of the block placed horizontally is:

Force constant of a spring is 100 N//m . If a 10kg block attached with the spring is at rest, then find extension in the spring. ( g= 10 m//s^(2) )

The system is released from rest with spring intially in its natural length. If mass of the block m = 10 kg. and spring constant k = 100 N//m , then maximum extension in spring is :

A massless spring with a force constant K = 40N//m hangs vertically from the ceiling.A 0.2 kg block is attached to the end of the spring and held in such a position that the spring has its natural length and suddenyl released. The maximum elastic strain energy stored in the spring is (g=10 m//s^(2))