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A particle is attached with a string of ...

A particle is attached with a string of length `l` which is fixed at point `O` on an inclined plane what minimum velocity should be given to the particle along the incline so that it may complete a circle on inclined plane `(` plane is smooth and initially particle was resting on the inclined plane . `)`

A

`sqrt(5gl)`

B

`sqrt((5gl)/(2))`

C

`sqrt((5sqrt(3gl))/(2))`

D

`sqrt(4gl)`

Text Solution

Verified by Experts

The correct Answer is:
B

The side view of circular motion is as shown `:`

`T+mg sin theta = ( mv^(2))/(R)`
and by energy conservation `:`
`(1)/(2)mv_(i)^(2)=(1)/(2)mv^(2)+mg2R ( sin theta )`
for `v_(i)` to be minimum, `v` is minimum and hence `T=0`
`rArr v_(i)^(2)=5gR, sin theta`
`rArr v_(i)")"_(min)=sqrt((5gl)/(2)) Ans. `
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Knowledge Check

  • The ratio of the range of the particle and its maximum range in the inclined plane is:

    A
    `1:2`
    B
    `1:sqrt(2)`
    C
    `1:sqrt(3)`
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    `(4u^2sqrt(3 - 1))/(9 g)`.
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    `(2 u^2sqrt(5 - 1))/(8 g)`.
    D
    `(2 u^2sqrt(3 - 1))/(3 g)`
  • A particle of mass m attached to a string of length l is descending circular motion on a smooth plane inclined at an angle alpha with the horizontal. For the particle to reach the highest point its velocity at the lowest point should exceed.

    A
    `sqrt(5gl)`
    B
    `sqrt(5gl(cos alpha+1))`
    C
    `sqrt(5gl//tan alpha)`
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