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A car moves around a curve at a constant...

A car moves around a curve at a constant speed. When the car goes around the arc subtending `60^(@)` at the centre, then the ratio of magnitude of instantaneous acceleration to average acceleration over the `60^(@)` arc is `:`

A

`(pi)/(3)`

B

`(pi)/(6)`

C

`(2pi)/(3)`

D

`(5pi)/(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
`|vec(Delta)V|=sqrt(v^(2)+v^(2)-2v^(2)cos 60^(@))=v`
`vec(a_(avg))=(|Deltavec(v)|)/(Deltat)=(v)/(t)=(3v^(2))/(piR)rArr a_(i)=(v^(2))/(R),(a_(i))/(a_(av))`
`=(v^(2)pi R)/(Rxx3v^(2))=(pi)/(3)`
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