In the figure shown, coefficient of restitution between A and B is `e=1/2`, then

Options

A. velocity of `B` after collision is `(v)/(2)`
B. impulse on one of the balls during collision is `(3)/(4)mv`
C. loss of kinetic energy in the collision is `(3)/(16)mv^(2)`
D. loss of kinetic energy in the collision is `(1)/(4)mv^(2)`

Answer

B, C

Explanation

After collision

By momentum conseration in horizontal direction
`V=V_(1)+V_(2) ……(1)`
and `e=(V_(2)-V_(1))/(V)=(1)/(2) .....(ii)`
By `(i)` and `(ii) V_(2)=(3V)/(4)`
`=m((3V)/(4))` and loss in `K.E.`
`=(3)/(16)mV^(2)`