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A man is standing on a cart of mass doub...

A man is standing on a cart of mass double the mass of the man. Initially car is at rest on the smooth ground. Now man jumps with relative velocity `'v'` horizontaly towards right with respect to cart. Find the work done by man during the process of jumping.

Text Solution

Verified by Experts

The correct Answer is:
`(mv^(2))/(3)`
Let the velocity of man after by man `=` change in `K.E.` of system

`=(1)/(2) m u^(2)+(1)/(2) 2 m (v-u)^(2)`
`=(1)/(2) m ((2v)/(3))^(2)+(1)/(2)2m((v)/(3))^(2)=(mv^(2))/(3)Ans.`
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