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As shown in the figure a body of mass m...

As shown in the figure a body of mass `m` moving horizontally with speed `sqrt(3) m//s` hits a fixed smooth wedge and goes up with a velocity `1v_(t)` in the vertical direction. If `/_` of wedge is `30^(@)`, the velocity `v_(f)` will be `:`

A

`sqrt(3)m//s`

B

`3m//s`

C

`(1)/(sqrt(3))m//s`

D

this is not possible

Text Solution

Verified by Experts

The correct Answer is:
D
Velocity along the plane does not change
So `sqrt(3)Sin f o^(@)=V_(1)sin 30^(@)`
`rArrV_(1)=3m//sgt sqrt(3)m//s`
Which in impossible `:. Ans. (D)`
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