A particle of mass m is given initial horizontal velocity of magnitude u as shown in the figure. It transfers to the fixed inclined plane without a jump, that is, its trajectory changes sharply from the horizontal line to the inclined line. All the surfaces are smooth and`90^(@) ge theta gt 0^(@)`. Then the height to which the particle shall rise on the inclined plane (assume the length of the inclined plane to be very large)

Options

A. increases with increase in `theta`
B. decreases with increase in `theta`
C. is independent of `theta`
D. data insufficient

Answer

B

Explanation

Just before the particle transfers to inclined surface, we resolve its velocity along and normal to the plane.

For the trajectory of the particles to sharply change from the horizontal line to be inclined line, the impact of the particle with inclined plane should reduce the `usin theta `component of velocity to zero. Hence the particle moves up the incline with speed `u cos theta`.
Hence as `theta` increases, the height to which the particle rises shall decrease.