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A uniform semicircular disc of mass 'm' ...

A uniform semicircular disc of mass `'m'` and radius `'R'` is shown in the figure. Find out its moment of inertia about.
`(a)` axis `'AB' (` shown in the figure `0` which passes through geometrical centre and lies in the plane of the disc
`(b)` axis `'CD'` which passes through its centre of mass and it is perpendicular to the plane of the disc.

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D

(a) `I_(AB)=(1)/(4)mR^(2)` ...Ans (b) `I_(CD)=(1)/(2)mR^(2)-m((4R)/(3pi))^(2)`
by parallel axis Theorem ……Ans.
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