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Find the acceleration of slid right circ...

Find the acceleration of slid right circular roller `A`, weighing `12kg` when it is being pulley by another weight `B (6 kg)` along the horizontal plane as in figure `(` pulley in massless `)`. The weight `B` is attached to the end of a string wound around the circularference of roller. Assume there is no slipping of the roller and the string is inextensible.

Text Solution

Verified by Experts

The correct Answer is:
`a=(20)/(7)` or `(2g)/(7)`

`T2R=[(12R^(2))/(2)+12R^(2)]alpha`
`T2R=18R^(2)alpha`
`6g-T=6xx2alphaR`
`T=60-12alphaR`
`T=9alphaR`
`9alphaR=60-12alphaR`
`alphaR=(60)/(21)=(20)/(7)`
` a=(20)/(7)or (2g)/(7)`
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