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For the previous question, the accelerat...

For the previous question, the acceleration of the particle at any time `t` is :

A

` -0.8 m//s^(2)`

B

`0.8 m//s^(2)`

C

`-0.6 m//s^(2)`

D

`0.5 m//s^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`(ds)/(dt)=15-0.8 t=7=v`
`8=0.8t`
`t=10` second
`a=(d^(2)s)/(dt^(2))=-0.8 m//s_(2)`.
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