The acceleration of paticle varies with time as :
`a(t) = 3t^(2) +4`
If the initial velocity of particle is `2 m//s`, find the velocity of particle at `t = 3sec`.

Options

A. `41 m//s`
B. `4 m//s`
C. `39 m//s`
D. `27 m//s`

Answer

A

Explanation

`a(t)=3t_(2)+4`
`(dv)/(dt)=3t_(2)+4`
`underset(2)overset(v)(int)dv =underset(0)overset(3)(int)(3t^(2)+4)dt`
`v-t=t^(3)+4t|_(0)^(3)=27+12 rArr v=41//s`.