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Find the maximum height reached by a par...

Find the maximum height reached by a particle which is thrown vertically upwards with the velocity of `20 m//s` (take `g= 10 m//s^(2)`).

A

40 m

B

10 m

C

20 m

D

zero

Text Solution

Verified by Experts

The correct Answer is:
C
`H=(u^(2))/(2g)=((20)^(2))/(2 xx 10)=20 m`.
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