A metal coin at the bottom of a beaker filled with a liquid of refractive index `4//3` to height of `6 cm`. To an observer looking from above the surface of the liquid, coin will appear at a depth of (consider paraxial rays).

Options

A. `7.5 cm`
B. `6.75 cm`
C. `4.5 cm`
D. `1.5 cm`

Answer

C

Explanation

Here : Actual depth of liquid `h =6 cm`,
Refractive, index of the liquid `= (4)/(3)`
Using the relation
`mu=("actual depth(h)")/("apparent depth(x)")`
or `x=h xx (3)/() =6 xx (3)/(4) =4.5 cm`.