A beam of light travelling with speed `c` in vacuum encounters a glass medium at an angle of incidence `60^(@)`. If the speed of light in the medium is `(c)/(sqrt(3))`, then the angle between the reflected and the refracted beams is :

Options

A. `30^(@)`
B. `60^(@)`
C. `90^(@)`
D. `120^(@)`

Answer

C

Explanation

`mu = sqrt(3)`
`(A) sin 60^(@) = sqrt(3) sin r`
`r = 30^(@) rArr theta = 90^(@)`.