A particle is moving along a straight line with constant acceleration. At the end of tenth second its velocity becomes `20 m//s` and tenth second it travels a distance od `10 m`. Then the acceleration of the particle will be.

Options

A. `10 m//s^(2)`
B. `20 m//s^(2)`
C. `(1)/(5) m//s^(2)`
D. `3.8 m//s^(2)`

Answer

B

Explanation

`v= u + at`
`rArr 20 =u+a xx 10` ….(1)
`S_(n) =u + (a)/(2) (2n -1)`
`rArr 10 =u + (a)/(2)(2 xx 10-1)` ….(2)
on solving (1) and (2) we get
`a = 20 m//s_(2)`.