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Two stones are thrown vertically upwards...

Two stones are thrown vertically upwards simultaneously from the same point on the ground with initial speed `u_(1) = 30 m//sec` and `u_(2) = 50 m//sec`. Which of the curve represent correct variation (for the time interval in which both reach the ground) of
`(x_(2) - x_(1))` = the relative position of second stone with respect to first with time (t)
`(v_(2) - v_(1))` = the relative velocity of second stone with respect to first with time (t).
Assuming that stones do not rebound after hitting.

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
A, D
While both the stones are in flight `a_(1) =g` and `a_(2) =g`
So `a_("rel") = 0 rArr V_("rel")` = constant
`rArr x_("rel") =` (const) t
`rArr` Curve of `x_("rel") v//s t` will be straight line. `X_("rel")` will be straight line.
After the first particle drops on ground, the seperation `(x_("rel"))` will decrease parabolically (due to gravitational acceleration) and finally becomes zero.
and `V_("rel")` = slope of `x_("rel") v//s t`
`x_("rel") t`
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